[FG] count to 2018 before its 2018

stop making me do math
17

 

6x3

 

x + 1 = 20
(x + 1)^2 = 400
(x + 1)^2 + 41 = 441
sqrt[(x + 1)^2 + 41] = 21
sqrt[(x + 1)^2 + 41]/7 = 3
sqrt[(x + 1)^2 + 41]/7 - 2 = 1
log{sqrt[(x + 1)^2 + 41]/7 - 2} = 0
cos((log{sqrt[(x + 1)^2 + 41]/7 - 2})) = 1

X=19

 

(10/2)*4

 

2x = k

k = 22- 8√7

k - 22 = -8√7

(k-22)² = (-8√7)

k² - 44k + 484 = 448

k² - 44k = 448-484

k² - 44k = -36

k³ - 44k² = -36k

k³ - 44k² + 36k = 0

k³ - 49k² +5k² + 8k + 28k = 0

k³ + 5k² + 8k = 49k² - 28k

k³ + 4k² + k² + 4k + 4k = 49k² - 28k

k³ + 4k² + k² + 4k + 4k + 4 - 4 = 49k² - 28k

k³ + 4k² + k² + 4k + 4k + 4 = 49k² - 28k + 4

k³ + 4k² + k² + 4k + 4k + 4 = (7k - 2)²

(1+k)(k² + 4k + 4) = (7k - 2)²

(1+k)(k + 2)² = (7k - 2)²

(1+k) = (7k-2)²/(k+2)²

(1 + 2sinxcosx) = (7k-2)²/(k+2)²

(sin²x + cos²x + 2sinxcosx) = (7k-2)²/(k+2)²

(sinx + cosx)² = (7k-2)²/(k+2)²

(sinx + cosx) = (7k-2)/(k+2)

sinx + cosx = (7k -2)/k / (k+2)/k)

sinx + cosx = (7 - 2/k) / (1+2/k)

(sinx + cosx) (1 + 2/k) = 7 - 2/k

sinx + cosx + 2sinx/k + 2cosx/k = 7 - 2/k

sinx + cosx + 2/k(sinx + cosx) + 2/k = 7

sinx + cosx + 2/k(sinx + cosx + 1) = 7

sinx + cosx + 2/k(sinx + cosx + sin²x + cos²x) = 7

sinx + cosx + 2/2sinxcos (sinx + cosx + sin²x + cos²x) = 7

sinx + cosx + 1/cosx + 1/sinx + sinx/cosx + cosx/sinx = 7

sinx+cosx+secx+cosecx+tanx+cotx = 7

sinx + cosx + secx + cosecx + tanx + cotx = 7

3(sinx + cosx + secx + cosecx + tanx + cotx) = 21

 

22. Im boring.

 

23

 

24

 

25

 

26

 

Tfw you try out different buttons on your calculator that you got for christmas

27

 

28

 

yasss 29

 

30 cooey must be bored

 

32

 

33(3)

 

34

 

35

 

3x5-2+4

 

37